Langgraph Human In The Loop

• interrupt(value) — pauses execution, surfaces a value to the caller
• Command(resume=value) — resumes execution, providing the value back to interrupt()
• Checkpointer — required to save state while paused
• Thread ID — required to identify which paused execution to resume

Requirements

Three things are required for interrupts to work:

1. Checkpointer — compile with checkpointer=InMemorySaver() (dev) or PostgresSaver (prod)
2. Thread ID — pass {"configurable": {"thread_id": "..."}} to every invoke/stream call
3. JSON-serializable payload — the value passed to interrupt() must be JSON-serializable

Basic Interrupt + Resume

interrupt(value) pauses the graph. The value surfaces in the result under __interrupt__. Command(resume=value) resumes — the resume value becomes the return value of interrupt().

Critical: when the graph resumes, the node restarts from the beginning — all code before interrupt() re-runs.

pythonCopy code
from langgraph.types import interrupt, Command
from langgraph.checkpoint.memory import InMemorySaver
from langgraph.graph import StateGraph, START, END
from typing_extensions import TypedDict

class State(TypedDict):
    approved: bool

def approval_node(state: State):
    # Pause and ask for approval
    approved = interrupt("Do you approve this action?")
    # When resumed, Command(resume=...) returns that value here
    return {"approved": approved}

checkpointer = InMemorySaver()
graph = (
    StateGraph(State)
    .add_node("approval", approval_node)
    .add_edge(START, "approval")
    .add_edge("approval", END)
    .compile(checkpointer=checkpointer)
)

config = {"configurable": {"thread_id": "thread-1"}}

# Initial run — hits interrupt and pauses
result = graph.invoke({"approved": False}, config)
print(result["__interrupt__"])
# [Interrupt(value='Do you approve this action?')]

# Resume with the human's response
result = graph.invoke(Command(resume=True), config)
print(result["approved"])  # True

typescriptCopy code
import { interrupt, Command, MemorySaver, StateGraph, StateSchema, START, END } from "@langchain/langgraph";
import { z } from "zod";

const State = new StateSchema({
  approved: z.boolean().default(false),
});

const approvalNode = async (state: typeof State.State) => {
  // Pause and ask for approval
  const approved = interrupt("Do you approve this action?");
  // When resumed, Command({ resume }) returns that value here
  return { approved };
};

const checkpointer = new MemorySaver();
const graph = new StateGraph(State)
  .addNode("approval", approvalNode)
  .addEdge(START, "approval")
  .addEdge("approval", END)
  .compile({ checkpointer });

const config = { configurable: { thread_id: "thread-1" } };

// Initial run — hits interrupt and pauses
let result = await graph.invoke({ approved: false }, config);
console.log(result.__interrupt__);
// [{ value: 'Do you approve this action?', ... }]

// Resume with the human's response
result = await graph.invoke(new Command({ resume: true }), config);
console.log(result.approved);  // true

Approval Workflow

A common pattern: interrupt to show a draft, then route based on the human's decision.

pythonCopy code
from langgraph.types import interrupt, Command
from langgraph.graph import StateGraph, START, END
from typing import Literal
from typing_extensions import TypedDict

class EmailAgentState(TypedDict):
    email_content: str
    draft_response: str
    classification: dict

def human_review(state: EmailAgentState) -> Command[Literal["send_reply", "__end__"]]:
    """Pause for human review using interrupt and route based on decision."""
    classification = state.get("classification", {})

    # interrupt() must come first — any code before it will re-run on resume
    human_decision = interrupt({
        "email_id": state.get("email_content", ""),
        "draft_response": state.get("draft_response", ""),
        "urgency": classification.get("urgency"),
        "action": "Please review and approve/edit this response"
    })

    # Process the human's decision
    if human_decision.get("approved"):
        return Command(
            update={"draft_response": human_decision.get("edited_response", state.get("draft_response", ""))},
            goto="send_reply"
        )
    else:
        # Rejection — human will handle directly
        return Command(update={}, goto=END)

typescriptCopy code
import { interrupt, Command, END, GraphNode } from "@langchain/langgraph";

const humanReview: GraphNode<typeof EmailAgentState> = async (state) => {
  const classification = state.classification!;

  // interrupt() must come first — any code before it will re-run on resume
  const humanDecision = interrupt({
    emailId: state.emailContent,
    draftResponse: state.responseText,
    urgency: classification.urgency,
    action: "Please review and approve/edit this response",
  });

  // Process the human's decision
  if (humanDecision.approved) {
    return new Command({
      update: { responseText: humanDecision.editedResponse || state.responseText },
      goto: "sendReply",
    });
  } else {
    return new Command({ update: {}, goto: END });
  }
};

Validation Loop

Use interrupt() in a loop to validate human input and re-prompt if invalid.

pythonCopy code
from langgraph.types import interrupt

def get_age_node(state):
    prompt = "What is your age?"

    while True:
        answer = interrupt(prompt)

        # Validate the input
        if isinstance(answer, int) and answer > 0:
            break
        else:
            # Invalid input — ask again with a more specific prompt
            prompt = f"'{answer}' is not a valid age. Please enter a positive number."

    return {"age": answer}

Each Command(resume=...) call provides the next answer. If invalid, the loop re-interrupts with a clearer message.

pythonCopy code
config = {"configurable": {"thread_id": "form-1"}}
first = graph.invoke({"age": None}, config)
# __interrupt__: "What is your age?"

retry = graph.invoke(Command(resume="thirty"), config)
# __interrupt__: "'thirty' is not a valid age..."

final = graph.invoke(Command(resume=30), config)
print(final["age"])  # 30

typescriptCopy code
import { interrupt } from "@langchain/langgraph";

const getAgeNode = (state: typeof State.State) => {
  let prompt = "What is your age?";

  while (true) {
    const answer = interrupt(prompt);

    // Validate the input
    if (typeof answer === "number" && answer > 0) {
      return { age: answer };
    } else {
      // Invalid input — ask again with a more specific prompt
      prompt = `'${answer}' is not a valid age. Please enter a positive number.`;
    }
  }
};

Multiple Interrupts

When parallel branches each call interrupt(), resume all of them in a single invocation by mapping each interrupt ID to its resume value.

pythonCopy code
from typing import Annotated, TypedDict
import operator
from langgraph.checkpoint.memory import InMemorySaver
from langgraph.graph import START, END, StateGraph
from langgraph.types import Command, interrupt

class State(TypedDict):
    vals: Annotated[list[str], operator.add]

def node_a(state):
    answer = interrupt("question_a")
    return {"vals": [f"a:{answer}"]}

def node_b(state):
    answer = interrupt("question_b")
    return {"vals": [f"b:{answer}"]}

graph = (
    StateGraph(State)
    .add_node("a", node_a)
    .add_node("b", node_b)
    .add_edge(START, "a")
    .add_edge(START, "b")
    .add_edge("a", END)
    .add_edge("b", END)
    .compile(checkpointer=InMemorySaver())
)

config = {"configurable": {"thread_id": "1"}}

# Both parallel nodes hit interrupt() and pause
result = graph.invoke({"vals": []}, config)
# result["__interrupt__"] contains both Interrupt objects with IDs

# Resume all pending interrupts at once using a map of id -> value
resume_map = {
    i.id: f"answer for {i.value}"
    for i in result["__interrupt__"]
}
result = graph.invoke(Command(resume=resume_map), config)
# result["vals"] = ["a:answer for question_a", "b:answer for question_b"]

typescriptCopy code
import { Command, END, MemorySaver, START, StateGraph, interrupt, isInterrupted, INTERRUPT, Annotation } from "@langchain/langgraph";

const State = Annotation.Root({
  vals: Annotation<string[]>({
    reducer: (left, right) => left.concat(Array.isArray(right) ? right : [right]),
    default: () => [],
  }),
});

function nodeA(_state: typeof State.State) {
  const answer = interrupt("question_a") as string;
  return { vals: [`a:${answer}`] };
}

function nodeB(_state: typeof State.State) {
  const answer = interrupt("question_b") as string;
  return { vals: [`b:${answer}`] };
}

const graph = new StateGraph(State)
  .addNode("a", nodeA)
  .addNode("b", nodeB)
  .addEdge(START, "a")
  .addEdge(START, "b")
  .addEdge("a", END)
  .addEdge("b", END)
  .compile({ checkpointer: new MemorySaver() });

const config = { configurable: { thread_id: "1" } };

const interruptedResult = await graph.invoke({ vals: [] }, config);

// Resume all pending interrupts at once
const resumeMap: Record<string, string> = {};
if (isInterrupted(interruptedResult)) {
  for (const i of interruptedResult[INTERRUPT]) {
    if (i.id != null) {
      resumeMap[i.id] = `answer for ${i.value}`;
    }
  }
}
const result = await graph.invoke(new Command({ resume: resumeMap }), config);
// result.vals = ["a:answer for question_a", "b:answer for question_b"]

User-fixable errors use interrupt() to pause and collect missing data — that's the pattern covered by this skill. For the full 4-tier error handling strategy (RetryPolicy, Command error loops, etc.), see the fundamentals skill.

Side Effects Before Interrupt Must Be Idempotent

When the graph resumes, the node restarts from the beginning — ALL code before interrupt() re-runs. In subgraphs, BOTH the parent node and the subgraph node re-execute.

Do:

• Use upsert (not insert) operations before interrupt()
• Use check-before-create patterns
• Place side effects after interrupt() when possible
• Separate side effects into their own nodes

Don't:

• Create new records before interrupt() — duplicates on each resume
• Append to lists before interrupt() — duplicate entries on each resume

pythonCopy code
# GOOD: Upsert is idempotent — safe before interrupt
def node_a(state: State):
    db.upsert_user(user_id=state["user_id"], status="pending_approval")
    approved = interrupt("Approve this change?")
    return {"approved": approved}

# GOOD: Side effect AFTER interrupt — only runs once
def node_a(state: State):
    approved = interrupt("Approve this change?")
    if approved:
        db.create_audit_log(user_id=state["user_id"], action="approved")
    return {"approved": approved}

# BAD: Insert creates duplicates on each resume!
def node_a(state: State):
    audit_id = db.create_audit_log({  # Runs again on resume!
        "user_id": state["user_id"],
        "action": "pending_approval",
    })
    approved = interrupt("Approve this change?")
    return {"approved": approved}

typescriptCopy code
// GOOD: Upsert is idempotent — safe before interrupt
const nodeA = async (state: typeof State.State) => {
  await db.upsertUser({ userId: state.userId, status: "pending_approval" });
  const approved = interrupt("Approve this change?");
  return { approved };
};

// GOOD: Side effect AFTER interrupt — only runs once
const nodeA = async (state: typeof State.State) => {
  const approved = interrupt("Approve this change?");
  if (approved) {
    await db.createAuditLog({ userId: state.userId, action: "approved" });
  }
  return { approved };
};

// BAD: Insert creates duplicates on each resume!
const nodeA = async (state: typeof State.State) => {
  await db.createAuditLog({  // Runs again on resume!
    userId: state.userId,
    action: "pending_approval",
  });
  const approved = interrupt("Approve this change?");
  return { approved };
};

Subgraph re-execution on resume

When a subgraph contains an interrupt(), resuming re-executes BOTH the parent node (that invoked the subgraph) AND the subgraph node (that called interrupt()):

pythonCopy code
def node_in_parent_graph(state: State):
    some_code()  # <-- Re-executes on resume
    subgraph_result = subgraph.invoke(some_input)
    # ...

def node_in_subgraph(state: State):
    some_other_code()  # <-- Also re-executes on resume
    result = interrupt("What's your name?")
    # ...

typescriptCopy code
async function nodeInParentGraph(state: State) {
  someCode();  // <-- Re-executes on resume
  const subgraphResult = await subgraph.invoke(someInput);
  // ...
}

async function nodeInSubgraph(state: State) {
  someOtherCode();  // <-- Also re-executes on resume
  const result = interrupt("What's your name?");
  // ...
}

Command(resume) Warning

Command(resume=...) is the only Command pattern intended as input to invoke()/stream(). Do NOT pass Command(update=...) as input — it resumes from the latest checkpoint and the graph appears stuck. See the fundamentals skill for the full antipattern explanation.

Fixes

pythonCopy code
# WRONG
graph = builder.compile()

# CORRECT
graph = builder.compile(checkpointer=InMemorySaver())

typescriptCopy code
// WRONG
const graph = builder.compile();

// CORRECT
const graph = builder.compile({ checkpointer: new MemorySaver() });

pythonCopy code
# WRONG
graph.invoke({"resume_data": "approve"}, config)

# CORRECT
graph.invoke(Command(resume="approve"), config)

typescriptCopy code
// WRONG
await graph.invoke({ resumeData: "approve" }, config);

// CORRECT
await graph.invoke(new Command({ resume: "approve" }), config);

• Use interrupts without a checkpointer — will fail
• Resume without the same thread_id — creates a new thread instead of resuming
• Pass Command(update=...) as invoke input — graph appears stuck (use plain dict)
• Perform non-idempotent side effects before interrupt() — creates duplicates on resume
• Assume code before interrupt() only runs once — it re-runs every resume